If you consider two people, me (M) and him (H), you get two possibilities:

M H

——

M H (in my seat)

H M

which is 50% chance of me in my seat. However, if you consider three people and add Other guy (O), then there are 6 possibilities:

M H O

———

M H O (in my seat)

M O H (in my seat)

H M O

H O M

O H M

H M H

only 2 of which end up with me in my seat (~33%). For 4 people, you get 6 / 24 times I’m in my seat (25%), etc. Which gives us 1/N or “1 out of N” where N is the number of people. So in this case, I would say D) 1 out of 100.

]]>(N-2)(N-2)! out of (N-1)(N-1)!

which yields ~-9.146912e+157 for N = 100. Assuming I didn’t do something wrong (which I probably did), I’m going to pick E), for [Effectively] Zero.

Did you ever post a solution?

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